Numbers k such that (2^k - 1)^2 - 2 = 4^k - 2^(k+1) - 1 is prime.

Terms

a(0) =2a(1) =3a(2) =4a(3) =6a(4) =7a(5) =10a(6) =12a(7) =15a(8) =18a(9) =19a(10) =21a(11) =25a(12) =27a(13) =55a(14) =129a(15) =132a(16) =159a(17) =171a(18) =175a(19) =315a(20) =324a(21) =358a(22) =393a(23) =435a(24) =786a(25) =1459a(26) =1707a(27) =2923a(28) =6462a(29) =14289