Primes of the form (2^n + 1)^2 - 2 = 4^n + 2^(n+1) - 1.
A091514
Primes of the form (2^n + 1)^2 - 2 = 4^n + 2^(n+1) - 1.
Terms
- a(0) =2a(1) =7a(2) =23a(3) =79a(4) =1087a(5) =66047a(6) =263167a(7) =16785407a(8) =1073807359a(9) =17180131327a(10) =68720001023
External references
- oeis: A091514