Numbers k such that (2^k + 1)^2 - 2 = 4^k + 2^(k+1) - 1 is prime.

Terms

a(0) =0a(1) =1a(2) =2a(3) =3a(4) =5a(5) =8a(6) =9a(7) =12a(8) =15a(9) =17a(10) =18a(11) =21a(12) =23a(13) =27a(14) =32a(15) =51a(16) =65a(17) =87a(18) =180a(19) =242a(20) =467a(21) =491a(22) =501a(23) =507a(24) =555a(25) =591a(26) =680a(27) =800a(28) =1070a(29) =1650