The Hirzebruch numbers. a(n) = Product_{2 <= p <= n+1, p prime} p^floor(n / (p - 1)).
A091137
The Hirzebruch numbers. a(n) = Product_{2 <= p <= n+1, p prime} p^floor(n / (p - 1)).
Terms
- a(0) =1a(1) =2a(2) =12a(3) =24a(4) =720a(5) =1440a(6) =60480a(7) =120960a(8) =3628800a(9) =7257600a(10) =479001600a(11) =958003200
External references
- oeis: A091137