Let f(0) = 0, f(1) = 1 and for n > 1 let f(n) = (-1)*sum((-1)^(n+r)*f(r),r=0..n-2)/(n*(n-1)); sequence gives denominator of f(n).
A090765
Let f(0) = 0, f(1) = 1 and for n > 1 let f(n) = (-1)*sum((-1)^(n+r)*f(r),r=0..n-2)/(n*(n-1)); sequence gives denominator of f(n).
Terms
- a(0) =1a(1) =1a(2) =1a(3) =6a(4) =12a(5) =24a(6) =40a(7) =1008a(8) =3360a(9) =362880a(10) =181440a(11) =39916800a(12) =15966720a(13) =6227020800a(14) =32947200a(15) =261534873600a(16) =373621248000
External references
- oeis: A090765