Let b(0)=0; b(1)=1; b(n+2)=(e^g-1/e^g)*b(n+1)+b(n). a(n)=floor(b(n)).

A090427

Let b(0)=0; b(1)=1; b(n+2)=(e^g-1/e^g)*b(n+1)+b(n). a(n)=floor(b(n)).

Terms

    a(0) =0a(1) =1a(2) =1a(3) =2a(4) =4a(5) =7a(6) =13a(7) =24a(8) =43a(9) =76a(10) =137a(11) =244a(12) =435a(13) =774a(14) =1379a(15) =2457a(16) =4377a(17) =7796a(18) =13886a(19) =24732a(20) =44050a(21) =78456a(22) =139736a(23) =248880a(24) =443274a(25) =789503a(26) =1406162a(27) =2504477a(28) =4460655a(29) =7944750

External references