Let b(0) = 1, b(n) = b(n-1) + (-1)^(n-1)*b(n-1)/10; sequence gives numerator of b(n).

A090337

Let b(0) = 1, b(n) = b(n-1) + (-1)^(n-1)*b(n-1)/10; sequence gives numerator of b(n).

Terms

    a(0) =1a(1) =11a(2) =99a(3) =1089a(4) =9801a(5) =107811a(6) =970299a(7) =10673289a(8) =96059601a(9) =1056655611a(10) =9509900499a(11) =104608905489a(12) =941480149401

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