Let f(0) = 0, f(1) = 1 and for n > 1 let f(n) = (-1)*sum((-1)^(n+r)*f(r),r=0..n-2)/(n*(n-1)); sequence gives numerator of f(n).

A090295

Let f(0) = 0, f(1) = 1 and for n > 1 let f(n) = (-1)*sum((-1)^(n+r)*f(r),r=0..n-2)/(n*(n-1)); sequence gives numerator of f(n).

Terms

    a(0) =0a(1) =1a(2) =0a(3) =-1a(4) =1a(5) =-1a(6) =1a(7) =-17a(8) =41a(9) =-3359a(10) =1319a(11) =-234061a(12) =77141a(13) =-25222469a(14) =113513a(15) =-775879541a(16) =964485937a(17) =-6450310315a(18) =178425130799

External references