a(n+2) = F(n)*a(n+1) + F(n+1)*a(n) where F(n) = Fibonacci number (A000045) and a(0) = a(1) = 1.
A089127
a(n+2) = F(n)*a(n+1) + F(n+1)*a(n) where F(n) = Fibonacci number (A000045) and a(0) = a(1) = 1.
Terms
- a(0) =1a(1) =1a(2) =1a(3) =2a(4) =4a(5) =14a(6) =62a(7) =422a(8) =4182a(9) =63228a(10) =1469976a(11) =53456724a(12) =3070947684a(13) =281012112132
External references
- oeis: A089127