a(n+2) = F(n+1)*a(n+1) + F(n)*a(n) where F(n) = Fibonacci number (A000045), a(0) = a(1) = 1.
A089126
a(n+2) = F(n+1)*a(n+1) + F(n)*a(n) where F(n) = Fibonacci number (A000045), a(0) = a(1) = 1.
Terms
- a(0) =1a(1) =1a(2) =1a(3) =2a(4) =5a(5) =19a(6) =110a(7) =975a(8) =13555a(9) =297330a(10) =10393875a(11) =581772345a(12) =52349401830
External references
- oeis: A089126