a(n+2) = a(n+1) + F(n+1)*a(n), where F = Fibonacci number (A000045) and a(0) = a(1) = 1.
A089125
a(n+2) = a(n+1) + F(n+1)*a(n), where F = Fibonacci number (A000045) and a(0) = a(1) = 1.
Terms
- a(0) =1a(1) =1a(2) =2a(3) =3a(4) =7a(5) =16a(6) =51a(7) =179a(8) =842a(9) =4601a(10) =33229a(11) =286284a(12) =3243665a(13) =44468561a(14) =800242506a(15) =17564890003a(16) =505712818663
External references
- oeis: A089125