a(0)=2, a(1)=1, a(n+2)=floor[(e-1/e)*a(n+1)+a(n-2)].
A085421
a(0)=2, a(1)=1, a(n+2)=floor[(e-1/e)*a(n+1)+a(n-2)].
Terms
- a(0) =2a(1) =1a(2) =4a(3) =10a(4) =27a(5) =73a(6) =198a(7) =538a(8) =1462a(9) =3974a(10) =10802a(11) =29363a(12) =79816a(13) =216962a(14) =589764a(15) =1603144a(16) =4357797a(17) =11845720a(18) =32200005a(19) =87528688a(20) =237927642a(21) =646754385a(22) =1758060692a(23) =4778904432a(24) =12990409077a(25) =35311592938a(26) =95986861417
External references
- oeis: A085421