For k not divisible by 10, let f(k) be the number obtained by moving the last digit of k to the front. Then a(n) is the smallest k > 0, made of nonzero digits, such that for all 1 <= i < n, i+1 divides f^i(k).

A084392

For k not divisible by 10, let f(k) be the number obtained by moving the last digit of k to the front. Then a(n) is the smallest k > 0, made of nonzero digits, such that for all 1 <= i < n, i+1 divides f^i(k).