Consider recurrence b(0) = (2n+1)/4, b(n) = b(0)*ceiling(b(n-1)); sequence gives first integer reached (or -1 if no integer is ever reached).

A081851

Consider recurrence b(0) = (2n+1)/4, b(n) = b(0)*ceiling(b(n-1)); sequence gives first integer reached (or -1 if no integer is ever reached).

Terms

    a(0) =5a(1) =7a(2) =36a(3) =1711985a(4) =13a(5) =15a(6) =1700a(7) =114a(8) =168a(9) =42000323a(10) =275a(11) =324a(12) =58a(13) =62a(14) =23658393a(15) =6055a(16) =58311963a(17) =9321a(18) =121770a(19) =13760a(20) =135a(21) =141a(22) =1960a(23) =344148a(24) =5734229a(26) =8825709a(28) =244a(29) =252a(31) =105432399233a(32) =27538521

External references