Consider recurrence b(0) = (2n+1)/2, b(n) = b(0)*ceiling(b(n-1)); sequence gives first integer reached.

A081849

Consider recurrence b(0) = (2n+1)/2, b(n) = b(0)*ceiling(b(n-1)); sequence gives first integer reached.

Terms

    a(0) =3a(1) =20a(2) =14a(3) =468a(4) =33a(5) =299a(6) =60a(7) =47328a(8) =95a(9) =1218a(10) =138a(11) =25475a(12) =189a(13) =3161a(14) =248a(15) =20830128a(16) =315a(17) =6512a(18) =390a(19) =181138a(20) =473a(21) =11655a(22) =564a(23) =9015167a(24) =663a(25) =18974a(26) =770a(27) =671745a(28) =885a(29) =28853

External references