Let b(n)=floor((3/2)^n), c(n)=floor((4/3)^n), d(n)=floor((5/4)^n); sequence gives values of n such that b(n+1)/b(n)=3/2, c(n+1)/c(n)=4/3 and d(n+1)/d(n)=5/4.
A081724
Let b(n)=floor((3/2)^n), c(n)=floor((4/3)^n), d(n)=floor((5/4)^n); sequence gives values of n such that b(n+1)/b(n)=3/2, c(n+1)/c(n)=4/3 and d(n+1)/d(n)=5/4.
Terms
- a(0) =162a(1) =172a(2) =204a(3) =328a(4) =403a(5) =414a(6) =809a(7) =835a(8) =840a(9) =854a(10) =1111a(11) =1117a(12) =1160a(13) =1188a(14) =1192a(15) =1270a(16) =1294a(17) =1311a(18) =1351a(19) =1409a(20) =1469a(21) =1478a(22) =1508a(23) =1605a(24) =1614a(25) =1769a(26) =1842a(27) =1961a(28) =2065a(29) =2226
External references
- oeis: A081724