a(n) = ((p-1)!/(2*p^2)) * Sum_{j=1..p-1} 1/j where p is the n-th prime.
A079303
a(n) = ((p-1)!/(2*p^2)) * Sum_{j=1..p-1} 1/j where p is the n-th prime.
Terms
- a(0) =1a(1) =18a(2) =43920a(3) =4397760a(4) =122377651200
External references
- oeis: A079303
A079303
a(n) = ((p-1)!/(2*p^2)) * Sum_{j=1..p-1} 1/j where p is the n-th prime.