Average of squares of successive primes: a(n) = (prime(n+1)^2 + prime(n)^2)/2, with n >= 2.
A075892
Average of squares of successive primes: a(n) = (prime(n+1)^2 + prime(n)^2)/2, with n >= 2.
Terms
- a(0) =17a(1) =37a(2) =85a(3) =145a(4) =229a(5) =325a(6) =445a(7) =685a(8) =901a(9) =1165a(10) =1525a(11) =1765a(12) =2029a(13) =2509a(14) =3145a(15) =3601a(16) =4105a(17) =4765a(18) =5185a(19) =5785a(20) =6565a(21) =7405a(22) =8665a(23) =9805a(24) =10405a(25) =11029a(26) =11665a(27) =12325a(28) =14449a(29) =16645
External references
- oeis: A075892