a(n) = a(n-1) + a(n-2) + a(n-3) + R(a(n-4)) where a(0)=a(1)=a(2)=a(3)=1 and R(n) (A004086) is the reverse of n.

A074863

a(n) = a(n-1) + a(n-2) + a(n-3) + R(a(n-4)) where a(0)=a(1)=a(2)=a(3)=1 and R(n) (A004086) is the reverse of n.

Terms

    a(0) =1a(1) =1a(2) =1a(3) =1a(4) =4a(5) =7a(6) =13a(7) =25a(8) =49a(9) =94a(10) =199a(11) =394a(12) =781a(13) =1423a(14) =3589a(15) =6286a(16) =11485a(17) =24601a(18) =52225a(19) =95137a(20) =230374a(21) =388378a(22) =766114a(23) =1458025a(24) =3085549a(25) =6183571a(26) =11138812a(27) =25616473a(28) =52394659a(29) =90903760

External references