a(n) = tau(Fibonacci(24*2^n))/(24*2^n) where tau(x) is the number of divisors of x (A000005(x)).
A074699
a(n) = tau(Fibonacci(24*2^n))/(24*2^n) where tau(x) is the number of divisors of x (A000005(x)).
Terms
- a(0) =3a(1) =7a(2) =32a(3) =144a(4) =5120a(5) =180224a(6) =3145728a(7) =3489660928
External references
- oeis: A074699