1/n * sum over d|n of {mu(n/d) * (5d)! / d!^5}.

A074653

1/n * sum over d|n of {mu(n/d) * (5d)! / d!^5}.

Terms

    a(0) =120a(1) =56640a(2) =56055960a(3) =76385030400

External references