a(1)=1, then "jump over next cube": a(n) = 2*(a(n-1)+1)^3-a(n-1).

A074488

a(1)=1, then "jump over next cube": a(n) = 2*(a(n-1)+1)^3-a(n-1).

Terms

    a(0) =1a(1) =15a(2) =8177

External references