Consider the recursion b(1,n) = 1, b(k+1,n) = b(k,n) + (b(k,n) reduced mod(k+n)); then there is a number x such that b(k,n) - b(k-1,n) is a constant x depending only on n, for k > y = A074483(n). Sequence gives values of x.

A074482

Consider the recursion b(1,n) = 1, b(k+1,n) = b(k,n) + (b(k,n) reduced mod(k+n)); then there is a number x such that b(k,n) - b(k-1,n) is a constant x depending only on n, for k > y = A074483(n). Sequence gives values of x.