Let b(1) = 1, b(k+1) = b(k) - k*trunc(k/b(k)+1), where trunc(x) = floor(x) if x>= 0, trunc(x) = ceiling(x) otherwise. Sequence a(n) gives the successive absolute values taken by b(k).

A073720

Let b(1) = 1, b(k+1) = b(k) - k*trunc(k/b(k)+1), where trunc(x) = floor(x) if x>= 0, trunc(x) = ceiling(x) otherwise. Sequence a(n) gives the successive absolute values taken by b(k).

Terms

    a(0) =1a(1) =11a(2) =58a(3) =293a(4) =1468a(5) =7343a(6) =36718a(7) =183593a(8) =917968a(9) =4589843a(10) =22949218a(11) =114746093a(12) =573730468a(13) =2868652343a(14) =14343261718a(15) =71716308593a(16) =358581542968

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