Let u(1) = u(2) = v(1) = v(2) = 1, u(n+2) = u(n)+v(n+1), v(n+2) = abs(u(n)-v(n+1)), then a(n) = u(n).

A072515

Let u(1) = u(2) = v(1) = v(2) = 1, u(n+2) = u(n)+v(n+1), v(n+2) = abs(u(n)-v(n+1)), then a(n) = u(n).

Terms

    a(0) =1a(1) =1a(2) =2a(3) =1a(4) =3a(5) =2a(6) =3a(7) =5a(8) =4a(9) =7a(10) =7a(11) =8a(12) =13a(13) =9a(14) =20a(15) =15a(16) =23a(17) =32a(18) =25a(19) =53a(20) =36a(21) =67a(22) =75a(23) =70a(24) =139a(25) =81a(26) =198a(27) =161a(28) =199a(29) =358

External references