Define C(n) by the recursion C(0) = 4*i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 4*(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.
A069961
Define C(n) by the recursion C(0) = 4*i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 4*(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.
Terms
- a(0) =1a(1) =17a(2) =20a(3) =73a(4) =169a(5) =464a(6) =1193a(7) =3145a(8) =8212a(9) =21521a(10) =56321a(11) =147472a(12) =386065a(13) =1010753a(14) =2646164a(15) =6927769a(16) =18137113a(17) =47483600a(18) =124313657a(19) =325457401a(20) =852058516a(21) =2230718177a(22) =5840095985a(23) =15289569808a(24) =40028613409a(25) =104796270449a(26) =274360197908a(27) =718284323305
External references
- oeis: A069961