Define C(n) by the recursion C(0) = 1 + I where I^2 = -1, C(n+1) = 1/(1+C(n)); then a(n) = (-1)^n/Im(C(n)) where Im(z) is the imaginary part of the complex number z.

A069921

Define C(n) by the recursion C(0) = 1 + I where I^2 = -1, C(n+1) = 1/(1+C(n)); then a(n) = (-1)^n/Im(C(n)) where Im(z) is the imaginary part of the complex number z.

Terms

    a(0) =1a(1) =5a(2) =10a(3) =29a(4) =73a(5) =194a(6) =505a(7) =1325a(8) =3466a(9) =9077a(10) =23761a(11) =62210a(12) =162865a(13) =426389a(14) =1116298a(15) =2922509a(16) =7651225a(17) =20031170a(18) =52442281a(19) =137295677a(20) =359444746a(21) =941038565a(22) =2463670945a(23) =6449974274a(24) =16886251873a(25) =44208781349a(26) =115740092170a(27) =303011495165a(28) =793294393321

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