a(n) = n^2*(n+1)!/(n^tau(n)) where tau(n) is the number of divisors of n.

A069141

a(n) = n^2*(n+1)!/(n^tau(n)) where tau(n) is the number of divisors of n.

Terms

    a(0) =2a(1) =6a(2) =24a(3) =30a(4) =720a(5) =140a(6) =40320a(7) =5670a(8) =403200a(9) =399168a(10) =479001600a(11) =300300a(12) =87178291200a(13) =6671808000a(14) =92990177280a(15) =86837751000

External references