Numbers k such that prime(k+1)-(k+1)*tau(k+1) = prime(k)-k*tau(k) where tau(k) = A000005(k) is the number of divisors of k.

A067293

Numbers k such that prime(k+1)-(k+1)*tau(k+1) = prime(k)-k*tau(k) where tau(k) = A000005(k) is the number of divisors of k.

Terms

    a(0) =2a(1) =14a(2) =38a(3) =85a(4) =93a(5) =122a(6) =135a(7) =213a(8) =243a(9) =301a(10) =387a(11) =394a(12) =537a(13) =603a(14) =694a(15) =766a(16) =778a(17) =903a(18) =963a(19) =1041a(20) =1083a(21) =1265a(22) =1346a(23) =1354a(24) =1382a(25) =1401a(26) =1412a(27) =1706a(28) =1713a(29) =1729

External references