Alternating sum of primes: a(1) = A000040(1) = 2 and a(n) = a(n-1) + A000040(n)*(-1)^n for n > 1.

Terms

a(0) =2a(1) =5a(2) =0a(3) =7a(4) =-4a(5) =9a(6) =-8a(7) =11a(8) =-12a(9) =17a(10) =-14a(11) =23a(12) =-18a(13) =25a(14) =-22a(15) =31a(16) =-28a(17) =33a(18) =-34a(19) =37a(20) =-36a(21) =43a(22) =-40a(23) =49a(24) =-48a(25) =53a(26) =-50a(27) =57a(28) =-52a(29) =61