a(n+1) = sum{j = 0,...n}[C(2n,2j)a(j)a(n-j)] with a(0) = 1.
A063902
a(n+1) = sum{j = 0,...n}[C(2n,2j)a(j)a(n-j)] with a(0) = 1.
Terms
- a(0) =1a(1) =1a(2) =2a(3) =10a(4) =80a(5) =1000a(6) =17600a(7) =418000a(8) =12848000a(9) =496672000a(10) =23576960000
External references
- oeis: A063902