Number of divisors of n-th term of sequence a(n+1) = a(n)*(a(0) + ... + a(n)) (A001697).
A062962
Number of divisors of n-th term of sequence a(n+1) = a(n)*(a(0) + ... + a(n)) (A001697).
Terms
- a(0) =1a(1) =1a(2) =2a(3) =4a(4) =12a(5) =40a(6) =160a(7) =792a(8) =9408a(9) =783360a(10) =55987200a(11) =35610624000
External references
- oeis: A062962