As p runs through the primes >= 5, sequence gives { numerator of Sum_{k=1..p-1} 1/k } / p^2.
A061002
As p runs through the primes >= 5, sequence gives { numerator of Sum_{k=1..p-1} 1/k } / p^2.
Terms
- a(0) =1a(1) =1a(2) =61a(3) =509a(4) =8431a(5) =39541a(6) =36093a(7) =375035183a(8) =9682292227a(9) =40030624861
External references
- oeis: A061002