In the '3x+1' problem, take the sequence of starting values which set new records for the "dropping time" (A060412); sequence gives associated maximal value reached in the trajectory with that start.

A060414

In the '3x+1' problem, take the sequence of starting values which set new records for the "dropping time" (A060412); sequence gives associated maximal value reached in the trajectory with that start.

Terms

    a(0) =2a(1) =8a(2) =26a(3) =4616a(4) =125252a(5) =1242458a(6) =20581856a(7) =12324038948a(8) =282667562a(9) =282667562a(10) =3611141594a(11) =8904120362a(12) =45119577824a(13) =8077577336a(14) =795853127168a(15) =44621605808a(18) =483308017730

External references