Sum_{k>=1} 1/(tanh(k*Pi) * k^(4n-1)) = Pi^(4n-1)*A057866(n)/A057867(n).
A057866
Sum_{k>=1} 1/(tanh(k*Pi) * k^(4n-1)) = Pi^(4n-1)*A057866(n)/A057867(n).
Terms
- a(0) =7a(1) =19a(2) =1453a(3) =13687a(4) =7708537a(5) =4472029801a(6) =149780635937
External references
- oeis: A057866