Consider recurrence b(0) = (2n+1)/2, b(n) = b(n-1)*floor(b(n-1)); sequence gives first integer reached.

A057016

Consider recurrence b(0) = (2n+1)/2, b(n) = b(n-1)*floor(b(n-1)); sequence gives first integer reached.

Terms

    a(0) =5a(1) =105a(2) =18a(3) =550935a(4) =39a(5) =2730a(6) =68a(8) =105a(9) =15939a(10) =150a(11) =943242300a(12) =203a(13) =53940a(14) =264a(16) =333a(17) =137085a(18) =410a(19) =41463649689a(20) =495a(21) =291870a(22) =588a(24) =689a(25) =550935a(26) =798a(27) =535022394030a(28) =915

External references