The recurrence b(k) = 10*b(k-1) + k^n with b(0)=0 has b(k)/10^k converging to a(n)/9^(n+1).

A055530

The recurrence b(k) = 10*b(k-1) + k^n with b(0)=0 has b(k)/10^k converging to a(n)/9^(n+1).

Terms

    a(0) =1a(1) =10a(2) =110a(3) =1410a(4) =22110a(5) =428610a(6) =10027710a(7) =274463010a(8) =8585407710a(9) =302029998210

External references