Consider the Diophantine equation x^3 + y^3 = z^3 + 1 (1<x<y<z) or 'Fermat near misses'. Arrange solutions by increasing values of z (see A050791), and increasing values of y in case of ties. Sequence gives values of y.
A050793
Consider the Diophantine equation x^3 + y^3 = z^3 + 1 (1<x<y<z) or 'Fermat near misses'. Arrange solutions by increasing values of z (see A050791), and increasing values of y in case of ties. Sequence gives values of y.
Terms
- a(0) =10a(1) =94a(2) =144a(3) =235a(4) =438a(5) =729a(6) =1537a(7) =1738a(8) =1897a(9) =2304a(10) =3518a(11) =4528a(12) =5625a(13) =8343a(14) =9036a(15) =9735a(16) =11664a(17) =11468a(18) =19386a(19) =21609a(20) =31180a(21) =35442a(22) =36864a(23) =33412a(24) =38782a(25) =35385a(26) =41167a(27) =44521a(28) =51762a(29) =59049
External references
- oeis: A050793