a(n) = a(1) + a(2) + ... + a(n-1) + a(m) for n >= 3, where m = 2^(p+1) + 2 - n and p is the smallest number such that 2^p < n - 1 <= 2^(p+1), starting with a(1) = 1 and a(2) = 2.

A049961

a(n) = a(1) + a(2) + ... + a(n-1) + a(m) for n >= 3, where m = 2^(p+1) + 2 - n and p is the smallest number such that 2^p < n - 1 <= 2^(p+1), starting with a(1) = 1 and a(2) = 2.