a(1) = 3; for n > 0, a(n+1) = a(n) * sum of digits of a(n).

A047912

a(1) = 3; for n > 0, a(n+1) = a(n) * sum of digits of a(n).

Terms

    a(0) =3a(1) =9a(2) =81a(3) =729a(4) =13122a(5) =118098a(6) =3188646a(7) =114791256a(8) =4132485216a(9) =148769467776

External references