a(1) = 11; for n > 0, a(n+1) = a(n) * sum of digits of a(n).

A047902

a(1) = 11; for n > 0, a(n+1) = a(n) * sum of digits of a(n).

Terms

    a(0) =11a(1) =22a(2) =88a(3) =1408a(4) =18304a(5) =292864a(6) =9078784a(7) =390387712a(8) =15615508480a(9) =671466864640

External references