a(1) = 8; for n > 1, a(n+1) = a(n) * sum of digits of a(n).

A047900

a(1) = 8; for n > 1, a(n+1) = a(n) * sum of digits of a(n).

Terms

    a(0) =8a(1) =64a(2) =640a(3) =6400a(4) =64000a(5) =640000a(6) =6400000a(7) =64000000a(8) =640000000a(9) =6400000000a(10) =64000000000a(11) =640000000000

External references