a(1) = 5; for n > 0, a(n+1) = a(n) * sum of digits of a(n).

A047897

a(1) = 5; for n > 0, a(n+1) = a(n) * sum of digits of a(n).

Terms

    a(0) =5a(1) =25a(2) =175a(3) =2275a(4) =36400a(5) =473200a(6) =7571200a(7) =166566400a(8) =5663257600a(9) =226530304000

External references