Primes p such that x^3 = 15 has a solution mod p.

Terms

a(0) =2a(1) =3a(2) =5a(3) =7a(4) =11a(5) =17a(6) =23a(7) =29a(8) =31a(9) =41a(10) =47a(11) =53a(12) =59a(13) =67a(14) =71a(15) =79a(16) =83a(17) =89a(18) =101a(19) =107a(20) =113a(21) =131a(22) =137a(23) =149a(24) =167a(25) =173a(26) =179a(27) =191a(28) =197a(29) =223