Let n = p_1*p_2*...*p_k be the prime factorization of n, with the primes sorted in descending order. Then a(n) = 2^(p_1 - 1)*3^(p_2 - 1)*...*A000040(k)^(p_k - 1).

A037019

Let n = p_1*p_2*...*p_k be the prime factorization of n, with the primes sorted in descending order. Then a(n) = 2^(p_1 - 1)*3^(p_2 - 1)*...*A000040(k)^(p_k - 1).

Terms

    a(0) =1a(1) =2a(2) =4a(3) =6a(4) =16a(5) =12a(6) =64a(7) =30a(8) =36a(9) =48a(10) =1024a(11) =60a(12) =4096a(13) =192a(14) =144a(15) =210a(16) =65536a(17) =180a(18) =262144a(19) =240a(20) =576a(21) =3072a(22) =4194304a(23) =420a(24) =1296a(25) =12288a(26) =900a(27) =960a(28) =268435456a(29) =720

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