Abundancy of n-th abundant number: sigma(k) - 2k for k such that this is > 0.

Terms

a(0) =4a(1) =3a(2) =2a(3) =12a(4) =12a(5) =19a(6) =10a(7) =12a(8) =28a(9) =12a(10) =8a(11) =48a(12) =12a(13) =4a(14) =51a(15) =12a(16) =26a(17) =56a(18) =4a(19) =54a(20) =60a(21) =17a(22) =12a(23) =2a(24) =64a(25) =24a(26) =12a(27) =120a(28) =60a(29) =72