Irregular triangle read by rows: there is a row for each value of n for which the aliquot sequence starting at n eventually reaches 1, giving the part of the sequence from n to 1.
A032451
Irregular triangle read by rows: there is a row for each value of n for which the aliquot sequence starting at n eventually reaches 1, giving the part of the sequence from n to 1.
Terms
- a(0) =1a(1) =2a(2) =1a(3) =3a(4) =1a(5) =4a(6) =3a(7) =1a(8) =5a(9) =1a(10) =7a(11) =1a(12) =8a(13) =7a(14) =1a(15) =9a(16) =4a(17) =3a(18) =1a(19) =10a(20) =8a(21) =7a(22) =1a(23) =11a(24) =1a(25) =12a(26) =16a(27) =15a(28) =9a(29) =4
External references
- oeis: A032451