a(n)=(# 3's)-(# 4's) in first n terms of A031269.

Terms

a(0) =0a(1) =0a(2) =1a(3) =1a(4) =1a(5) =1a(6) =2a(7) =2a(8) =3a(9) =2a(10) =2a(11) =2a(12) =2a(13) =1a(14) =1a(15) =1a(16) =1a(17) =2a(18) =2a(19) =1a(20) =1a(21) =1a(22) =2a(23) =1a(24) =1a(25) =0a(26) =0a(27) =1a(28) =2a(29) =2