a(n)=(# 2's)-(# 3's) in first n terms of A031269.

Terms

a(0) =0a(1) =1a(2) =0a(3) =0a(4) =0a(5) =0a(6) =-1a(7) =0a(8) =-1a(9) =-1a(10) =-1a(11) =-1a(12) =-1a(13) =-1a(14) =0a(15) =0a(16) =0a(17) =-1a(18) =0a(19) =0a(20) =0a(21) =0a(22) =-1a(23) =-1a(24) =-1a(25) =-1a(26) =-1a(27) =-2a(28) =-3a(29) =-3