a(n)=(# 3's)-(# 4's) in first n terms of A031253.

Terms

a(0) =0a(1) =1a(2) =1a(3) =1a(4) =1a(5) =1a(6) =1a(7) =0a(8) =0a(9) =0a(10) =0a(11) =1a(12) =2a(13) =2a(14) =3a(15) =3a(16) =4a(17) =3a(18) =2a(19) =2a(20) =1a(21) =2a(22) =2a(23) =2a(24) =2a(25) =2a(26) =2a(27) =2a(28) =2a(29) =2